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電磁気学

真空中の電磁気学ーEB対応・EH対応
物質中の電磁気学ーEB対応・EH対応

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Quantum Field Theory

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E16 related information

Properties of related particles

$$ \gamma^0 = \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix} , \gamma^j = \begin{pmatrix} 0 & \sigma_j \\ -\sigma_j & 0 \end{pmatrix} , \gamma_5 = \begin{pmatrix} -1 & 0 \\ 0 & 1 \end{pmatrix} $$ $$ \psi_L = \begin{pmatrix} \xi \\ 0 \end{pmatrix}, \psi_R = \begin{pmatrix} 0 \\ \bar{\eta} \end{pmatrix} $$

Dirac Representation

$$ \gamma^0 = \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix} , \gamma^j = \begin{pmatrix} 0 & \sigma_j \\ -\sigma_j & 0 \end{pmatrix} , \gamma_5 = \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix} $$ $$ \gamma^0 = \beta $$ $$ \gamma^k = \beta \alpha^k $$ $$ \gamma_5 = i\gamma^0\gamma^1\gamma^2\gamma^3 $$

Dirac matrices and $\alpha \beta$

Definitions $$ \sigma^{\mu\nu} = \frac{i}{2} [\gamma^\mu,\gamma^\nu] $$ $$ \phi \rightarrow \pi^0 e^+ e^- $$ $$ \eta (958) \rightarrow$$ $$ \eta (958) \rightarrow \gamma e^+ e^- $$ The following line is a sample:
When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$